38/(6-5x)^2=0

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Solution for 38/(6-5x)^2=0 equation:


D( x )

(6-(5*x))^2 = 0

(6-(5*x))^2 = 0

(6-(5*x))^2 = 0

(6-5*x)^2 = 0

6-5*x = 0 // - 6

-5*x = -6 // : -5

x = -6/(-5)

x = 6/5

x in (-oo:6/5) U (6/5:+oo)

38/((6-(5*x))^2) = 0

38/((6-5*x)^2) = 0

38 = 0

x belongs to the empty set

x belongs to the empty set

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